Answer:
Margin of error at 90% is 0.024
Margin of error at 99% is 0.037
Step-by-step explanation:
Sample size = 1076
A poll found that 64% of a random sample of 1076 adults said they believe in ghosts.
So, No. of adults said they believe ghosts = 
So, x = 688
n = 1076




z at 90% confidence is 1.64


So, margin of error at 90% is 0.024
Find the margin of error needed to be 99% confident.
z at 99% confidence is 2.58


So, margin of error at 99% is 0.037