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3 years ago

(-5/4)-2 Please help need fast answers

Mathematics

2 answers:

Mashcka [7]3 years ago

7 0

Answer:

-3.25

Step-by-step explanation:

(-1.25 - 2)

postnew [5]3 years ago

4 0

-3.25 I believe this is the answer

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What is 20/7 as a mixed number in simplest form?

cricket20 [7]

It would be: 20/7 = 2 6/7

In short, Your Answer would be 2 6/7

Hope this helps!

5 0

3 years ago

There are 6 gray keys for every 11 black keys. Also, the number of black keys is 2 less than twice the number of gray keys. Use

emmainna [20.7K]

$\text{ Answer: There are }12\text{ gray keys.}\\\\\text{ there are }22\text{ black keys.}$

Explanation:

Since we have given that

There are 6 gray keys for every 11 black keys .

So, the ratio will be 6:11

Let the number of gray keys be 6x

Let the number of black keys be 11x

Now, according to question,

$11x=2\times 2x-2\\\\11x=12x-2\\\\11x-12x=-2\\\\-x=-2\\\\x=2$

so,

$\text{ there are }6x=6\times 2=12\text{ gray keys.}\\\\\text{ there are }11x=11\times 2=22\text{ black keys.}$

8 0

3 years ago

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

ololo11 [35]

Answer:

The answer would be f(a)=-1

-AC I hope this helps<3

7 0

3 years ago

The hourly median power (in decibels) of received radio signals transmitted between two cities

trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

The 90th percentile of this distribution is of 136 dB.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.

There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.

In a lognormal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{\ln{X} - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = \sqrt{1.22}$

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence X when Z = 1.28.

$Z = \frac{\ln{X} - \mu}{\sigma}$

$1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}$

$\ln{X} - 3.5 = 1.28\sqrt{1.22}$

$\ln{X} = 1.28\sqrt{1.22} + 3.5$

$e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}$

$X = 136$

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the p-value of Z when X = 150, hence:

$Z = \frac{\ln{X} - \mu}{\sigma}$

$Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}$

$Z = 1.37$

$Z = 1.37$ has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, we have that $p = 0.9147, n = 10$ , and we want to find P(X = 6), then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065$

There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0

3 years ago

2. What is the slope in this equation? y =2x +1 y 2 х 1

Neporo4naja [7]

Answer:

the slope equals 2. otherwise known as the coefficient of x.

5 0

3 years ago