Question

Hello pls help meeee

Answer 1

The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).

Given that,

The function is (-x+3)/ (3x-2)

We have to find f(1) and f'(x).

Take the function expression

f(x)= (-x+3)/ (3x-2)

Taking x as 1 value

f(1)= (-1+3)/(3(1)-2)

f(1)=2/1

f(1)=1

Now, to get f'(x)

With regard to x, we must differentiate.

f(x) is in u/v

We know

u/v=(vu'-uv')/ v²        (formula)

f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²

f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4

f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4

f'(x)=2-9/ (9x²- 12x+4)

f'(x)=-7/ (9x²- 12x+4)

Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).

To learn more about function visit: brainly.com/question/14002287

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