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mafiozo [28]
3 years ago
14

Which is an equation for a line that is perpendicular to the graph of a line y=2x-3

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0

y = -1/2x - 3 is the correct equation

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Find the slope of the tangent to y= -7Sin(x)+2cos(x) at x= 3π/4
BaLLatris [955]
Y = -7sin(x) + 2cos(x)
y = -7sin(3π/4) + 2cos(3π/4)
y = -7sin(9.42/4) + 2cos(9.42/4)
y = -7sin(2.355) + 2cos(2.355)
y = -7(0.03698381721) + 2(0.9993158646)
y = -0.2588867205 + 1.998631729
y = 1.739745009
6 0
3 years ago
***I WILL GIVE BRAINIEST TO THE CORRECT ANSWER**
galben [10]

Answer:

2•15k

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Helppppppopppppppppppppppppp
salantis [7]
B is a correct answer
6 0
3 years ago
(PLEASE HELP) The table below - does it represent an exponential function?
Aliun [14]
Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.

The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.

If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.

n = 4
y = 2^(2*4)
y  =  2^8
y = 256

n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.

so y = 2^(2n) I think is an exponential function.
Sorry my explanation is so long.

6 0
4 years ago
NEEDED NOW
stealth61 [152]

Answer:

D. The velocity of the bike when Jack stopped pedaling.

Step-by-step explanation:

I took a test with this question and got it right .

8 0
3 years ago
Read 2 more answers
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