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3 years ago

What expression is equivalent to -0.2 - 4.9?

Mathematics

1 answer:

nasty-shy [4]3 years ago

6 0

Answer:

Step-by-step explanation:

Adding a negative is the same as subtracting a positive

Keep Change Change

ex. -9.2 - 6.7 = -9.2 + -6.7

Keep Change Change

-9.2 + -6.7

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135 miles on 4 gallons of gas

8_murik_8 [283]

To find out how many miles 1 gallon of gas uses we will divide.

135 ÷ 4 = 33.75

Check our work:-

33.75 × 4 = 135

So, 33.75 miles per gallon.

Hope I helped ya!!

3 0

2 years ago

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19. Write an equation to represent the relationship

balandron [24]

Answer:

y = x +3

Step-by-step explanation:

When you examine the table, you see that each y-value is 3 more than the corresponding x-value. This is represented in the equation ...

y = x +3

8 0

2 years ago

Please help my sister again I can’t stand her she’s making me mad

inna [77]

Answer:

I'm pretty sure it's dark blue. It says below so that implies negative.

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3 years ago

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If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$