Ask question

Ask question

All categories

soldi70 [24.7K]

3 years ago

15

Solve this and I'll give you brainliest!thank you!!!

2 answers:

lilavasa [31]3 years ago

8 0

I say it what’s the person said above me

krok68 [10]3 years ago

5 0

Answer: 146°

Step-by-step explanation:

A line is 180°

Since 34° is adjacent to DBC

subtract 34°

180 - 34 = 146

You might be interested in

Which do lenders take into account before issuing unsecured debt

inn [45]

Its creditworthiness

5 0

3 years ago

The winner of a gymnastics competition scored a total of 22.1 points. She won by 0.676 points.

weqwewe [10]

Answer:

21.424

Step-by-step explanation:

22.1 - 0.676 = 21.424

im not sure if it is correct but i think its like this

7 0

3 years ago

Find the value of the variables in the simplest form

STatiana [176]

Answer:

x = 3

Step-by-step explanation:

Using the tangent ratio in the right triangle and the exact value

tan60° = $\sqrt{3}$

tan60° = $\frac{opposite}{adjacent}$ = $\frac{x}{\sqrt{3} }$ = $\sqrt{3}$ ( multiply both sides by $\sqrt{3}$ )

x = 3

6 0

3 years ago

The number of pieces of dog food in a one-cup scoop is approximately Normally distributed with a mean of 205 pieces and a standa

Nastasia [14]

It’s C because you are just the best

8 0

3 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

3 years ago