Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
92% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
10/9 can be rewritten as 1 1/9, so it's closest to 1. 2/15 is really small, so close to 0.
Answer:
what is it asking???? it doesn't make sense
Answer: 2/3 times 4
Step-by-step explanation:
Answer:
4th choice
Step-by-step explanation:
Let f(x)=x^4 be the parent function.
This is what the following means:
n(x)=(x-3)^4 : The parent function has moved right 3.
h(x)=-x^4 : The parent function has been reflected over the x-axis.
------------------
Together (n and h):
m(x)=-(x-3)^4: The parent function has been reflected over the x-axis and moved right 4 units.
----------------
v(x)=(x-3)^4+5: The parent function has been moved right 3 units and up 5 units.
So you have g(x)=-(x+3)^4.
So this consists of a reflection across x-axis and has been shifted 3 units left.
