A system of linear equations has been graphed in the diagram. Determine a reasonable solution for the system of

The data set shows the numbers of yogurt pretzels in various bags.

Rainbow [258]

Answer:

B

Step-by-step explanation:

i believe the answer is B but I’m not sure

hope dis helps ^-^

6 0

2 years ago

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Three people become infected with a virus that spreads quickly. Each day that passes, the number of infected people doubles. How

avanturin [10]

$3x \times 2 = y$
this is what I would come up with because.
y=the number of people infected
x=the number of days that have passed

5 0

3 years ago

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Find C.

nasty-shy [4]

Answer:

$C=69.1^{\circ}$

Step-by-step explanation:

The Law of Cosines is given as:

$c^2=a^2+b^2-2ab\cos C$ .

Plugging in given values, we get:

$16^2=8^2+17^2-2\cdot 8\cdot 17\cdot \cos C,\\\cos C=\frac{-97}{-272},\\C=\arccos(\frac{97}{272}),\\C=\fbox{$69.1^{\circ}$}$ .

3 0

2 years ago

the expression 5n+2 can be used to find total cost in dollars of bowling where n is the number of games bowled 2 represents the

exis [7]

So justsubsitue 3 for n
5(3)+2
15+2
17
answer is 17

3 0

3 years ago

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A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust

AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let X = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts n = 8 potential customers per day.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...$

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

$P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488$

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

= 1 - P (X = 0) - P (X = 1)

$=1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869$

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

$P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305$

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

$E(X)=np=8\times 0.10=0.80$

Thus, the expected number of sales per day is 0.80.

7 0

2 years ago