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3 years ago

A system of linear equations has been graphed in the diagram. Determine a reasonable solution for the system of

Mathematics

1 answer:

BaLLatris [955]3 years ago

7 0

Answer:

Step-by-step explanation:

the point is closer to that number.

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R, S, Q and P are the midpoints of OC, CB, BA and OA respectively.

Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

Draw segment OB.

In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.

In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.

Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.

3 0

2 years ago

Marie has 5 apples, Toby takes 2 away. How many does he have less?

Natali [406]

Answer:

2less apples

Step-by-step explanation:

5-2=3. 3+2=5

8 0

3 years ago

Read 2 more answers

Joe has $70 in a savings account. The interest rate is 10% per year and is not compounded,

sladkih [1.3K]

Answer:

$28

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 10%/100 = 0.1 per year,

then, solving our equation

I = 70 × 0.1 × 4 = 28

I = $ 28.00

The simple interest accumulated

on a principal of $ 70.00

at a rate of 10% per year

for 4 years is $ 28.00.

8 0

3 years ago

Twice the sum of eight and three times a number is seventy six. What is the number

Dahasolnce [82]

From the question we can deduce the formula to be 16 + 3n = 76

3n - 76 - 16

3n = 60

n = 20

20 is the answer.

3 0

3 years ago

A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range

maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

5 0

3 years ago