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nekit [7.7K]
2 years ago
5

Abc is an equilateral triangle and has an area of 8/5. point d is the midpoint of side ab, point e is the midpoint of side bc, a

nd point f is the midpoint of side ac. what is the area of the parallelogram decf?
a.2/5
b.2/3
c.4/5
d.13/15
e.1
Mathematics
1 answer:
nlexa [21]2 years ago
6 0
Hello,

There are 4 congurent equilateral triangles in ABC and each has an area of (8/5)/4=2/5.
To form the parallelogram we need 2 triangles: 2* 4/5=4/5.

Answer C.
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3 years ago
Triangle FGH with vertices F(6,6), G(8,8), and H(8,3): (a) Reflection: in the line x = 5 (b) Translation: (x,y)→ (x - 7, y - 9)
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(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given

Part (a)

the rule for reflection of point (x,y) by the line x = p  is

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reflection by the line x = 5 ,

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Part (b)

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