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sveta [45]
3 years ago
13

The proof that triangle ABC is congruent to triangle CDA is shown. given a AB is parallel to cd and BC is parallel to DE prove t

riangle ABC is congruent to triangle CDA what is the missing reason in the proof
Mathematics
1 answer:
Tresset [83]3 years ago
3 0

Answer:

D) SSS congruence theorem

Step-by-step explanation:

Edge 2021

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A divided by 9= -4 plss solve
iragen [17]

Answer:

<h3>\boxed{ \bold{ \sf{ \huge{ \boxed{ a =  - 36}}}}}</h3>

Step-by-step explanation:

\sf{ \frac{a}{9}  =  - 4}

Apply cross product property

⇒\sf{a  =  - 4 \times 9}

Multiply the numbers

⇒\sf{a =  - 36}

Hope I helped!

Best regards!!

8 0
3 years ago
Solutions to ( x - 2 )² = -16​
drek231 [11]

Answer: There are no real solutions

4 0
3 years ago
Read 2 more answers
What polygon is formed when 2 equilateral triangles that are congruent and share a side
zalisa [80]

You form a rhombus.

Draw an equilateral triangle, and then mirror it around its base. All the sides are clearly equal, because they are all sides of the same equilateral triangle.

Moreover, the top and bottom angle are 60°, because they are angles of an equilateral triangle, while the left and right angles are 120, because they're 60+60 angles.

7 0
3 years ago
A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location
Deffense [45]

Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

The observed data is:

Location                      Observed sales (units)

Northside                                70

Pleasant Township                 75

Southwick                               70

I-90                                          50

Venice Avenue                       35

TOTAL                                   300

The test statistic for the Goodness of fit test is:

\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}

For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).

The sample size in this case is, <em>k</em> = 5.

The degrees of freedom is, (<em>k</em> - 1) = 4.

The level of significance is, <em>α</em> = 0.01.

The critical value of the test is:

\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277

**Use the Chi-square table.

Thus, the critical value is 13.277.

7 0
3 years ago
What is the solution to this equation log(2x-100)=3
Mnenie [13.5K]
Greeting to you! My name is Cecille and I’m here to answer that question

For more explanation, please see the attachment

5 0
2 years ago
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