Ask question

Ask question

All categories

sergij07 [2.7K]

1 year ago

13

Alfred is building a slide for a new park. He wants the height of the slide to be 8 feet, and he wants the horizontal distance a

long the ground to measure 10 feet.
After building the slide, Alfred decides the slide needs a vertical safety support and wants to use a 4-foot piece of wood to build the support. How far from the point where the base of the slide meets the ground should Alfred place the vertical support?

A: 20 Feet

B: 1.3 Feet

C: 5 Feet

D: 4 Feet

1 answer:

oksano4ka [1.4K]1 year ago

8 0

Answer:

5ft

Step-by-step explanation:

8/10=0.8

4/0.8=5

You might be interested in

Based on the measures provided in the diagram, determine the measure of AEG

MArishka [77]

Answer:

277°

Step-by-step explanation:

The measure of arc AEG = AB + BE + EF + FG

The central angle is congruent to the arc that subtends it

∠ ECB = 180° - 44° = 136° ( adjacent angles )

∠ECF = ∠ ACB = 44° ( vertical angles ), thus

AEG = 44° + 136° + 44° + 53° = 277°

8 0

3 years ago

If 4x + 8x + 12x + 16x is equal to 5 + 10 + 30 + 40 then what is the value of x

zloy xaker [14]

4x+8x+12x+16x=5+10+30+40

4x+8x+12x+16x= 85

40x=85

x= 85/40

x=2.125

7 0

2 years ago

875 rounded to nearest ten

velikii [3]

880
Underline the number in the tens place
look to the right
if number is greater than 5
add 1 to the underlined number
leave the numbers behind the underlined number zero

4 0

2 years ago

Read 2 more answers

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

(as a unit rate simplified) 24 bottles for $2.95

AysviL [449]

Answer:

Bottle unit: 8.14

Dollar unit: $0.12

Step-by-step explanation:

Dividing the equation, bottle on top for bottle and dollars on top for dollar.

7 0

2 years ago