See image for question.Please show workings and diagrams.
2 answers:
Answer:
- a) 258 km
- b) 267°
- c) 87°
Step-by-step explanation:
- <em>Refer to attached diagram (not to scale).</em>
- <em>Given details are reflected.</em>
<u>First find the measure of angle Q</u>
- m∠Q = 36° + (180° - 125°) = 91°
a) <u>Use law of cosines to find x:</u>
- x = √(160² + 200² - 2160*200*cos 91°) = 258 km (rounded)
<u>Use the law of sines to find the missing angles:</u>
- 258 / sin 91 = 160 / sin R = 200 / sin P
- m∠R = arcsin (160 sin 91° / 258) = 38°
- m∠P = 180° - (91° + 38°) = 51°
b) <u>Bearing P from R:</u>
- 360° - (55° + 38°) = 267°
c) <u>Bearing R from P:</u>
- 36° + 51° = 87°
You might be interested in
Answer:
i) Equation can have exactly 2 zeroes.
ii) Both the zeroes will be real and distinctive.
Step-by-step explanation:
is the given equation.
It is of the form of quadratic equation and highest degree of the polynomial is 2.
Now, FUNDAMENTAL THEOREM OF ALGEBRA
If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.
So, the equation can have exact 2 zeroes (roots).
Also, find discriminant D =
⇒ D = 37
Here, since D > 0, So both the roots will be real and distinctive.