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NISA [10]
3 years ago
10

What was the price of the camera after the increase?

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0
D 450 hope this helps you
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Help me please !!! Only right answer please
ella [17]
The answer is 4 like i sed last time stop making conversation nd get to work
4 0
3 years ago
If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a
kolbaska11 [484]

Answer:

<h2><em>2(3s-14)</em></h2>

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

8s-6 = 2s + 22+ ∠EBF

∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

<em></em>

<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>

8 0
3 years ago
JUST NEED THE ANSWER PLEASE I WILL MARK AS BRAINLIEST
finlep [7]
-49/15 -3 4/15...........
6 0
3 years ago
Read 2 more answers
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
The measure of angle KMJ??
Irina18 [472]
44

Assuming JM and LN are parallel, KMJ=MKN. MKN is part of a triangle where the other two values are defined (48 and 88). By subtracting these values from 180, we find the value of MKN is 44, which therefore is also the value of KMJ.
3 0
3 years ago
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