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NISA [10]
2 years ago
10

What was the price of the camera after the increase?

Mathematics
1 answer:
Pepsi [2]2 years ago
3 0
D 450 hope this helps you
You might be interested in
A theater seats 2,816 people. The first row has 26 seats while the last row has 150 seats. Assuming the number of seats per row
wolverine [178]

Answer:

The theater has 32 rows

Step-by-step explanation:

The rule of the sum of n terms of an arithmetic sequence is S_{n} = \frac{n}{2} (a + l), where

  • a is the first term
  • l is the last term
  • n is the number of the terms

∵ The number of seats per row follows an arithmetic sequence

∵ The first row has 26 seats

∴ a = 26

∵ The last row has 150 seats

∴ l = 150

∵ The theater seats are 2,816

∴ S_{n} = 2,816

→ Substitute these values in the rule of the sum above to find n

∵ 2,816 = \frac{n}{2}(26 + 150)

∴ 2,816 = \frac{n}{2}(176)

∴ 2,816 = 88n

→ Divide both sides by 88

∴ 32 = n

∵ n represents the number of the rows

∴ The theater has 32 rows

3 0
2 years ago
Whats the measure of
maxonik [38]
Acute angle i think about 60
8 0
2 years ago
What is the value of x? 1 2 x + 2 = x - 1 4 A) - 2 9 B) - 9 2 C) 1 9 D) 9 2
Volgvan
X=1.3
Hope this helps I not I’m truly sorry
6 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
Is 6 divisible by 36
andrew-mc [135]
In the terms you used, not unless you want an integer for an answer.
8 0
2 years ago
Read 2 more answers
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