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3 years ago

Can anyone tell me what this graph is in slope intercept form?

Mathematics

1 answer:

Eddi Din [679]3 years ago

6 0

Answer:

the standard form equation is 1/2x^2-x-3/2=0

the vertex form equation is 1/2(x-1)^2-2=0

Step-by-step explanation:

Unfortunately, this can't be written in slope intercept form but I can write it in standard form(ax^2+bx+c) or vertex form (a(x-h)+k)

The vertex is (1,-2)

I estimate a=1/2 because the graph was widened and that can only be done by a fraction.

So, 1/2(x-1)^2-2=0

To find it in standard form

foil (x-1)(x-1)= x^2-2x+1

Then multiply by 1/2(x^2-2x+1)= 1/2x^2-x+1/2-2

To add 1/2-2. You mulitply -2 by 2/2 which equals 1/2-4/2 which equals -3/2

So the standard form equation is 1/2x^2-x-3/2=0

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a football team gained 9 yards on one play and then lost 22 yards on the next.write a sum of intergers to find the overall chang

s2008m [1.1K]

Let x be the original position.

After the first play they gain 9 yards. The position can be represented by
x + 9

After the second play they lose 22 yards. The position can be represented by
x + 9 - 22 = x - 13

Therefore, in total they lost 13 yards.

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3 years ago

¿qué edificaciones se encuentran en el mundo con el aspecto de una parábola?

Oksana_A [137]

Answer:

Una parábolase obtienecuando se corta un cono de tal maneraque el corte sea paralelo auno de sus lados, como lo muestra la grafica de la Fig. No 10. Una vez que se ha observado a la parábola en la naturaleza, pasemos a estudiarla desde el punto de vista geométrico.

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3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

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3 years ago

Which scenarios have a negative correlation? Check all that apply. the number of calories consumed and the amount of weight lost

MA_775_DIABLO [31]

Answer:

A & E

Step-by-step explanation:

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3 years ago

Read 2 more answers

Graph the equation on the coordinate plane.y=2x-1

Yakvenalex [24]

This equation is written in slope intercept form

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

In this case:

slope (m) is 2

y-intercept (b) is (0, - 1)

To plot this on a coordinate plane plot the y-intercept (0, -1).

To graph the rest of the line you can use what you know about the slope. Rise up two units and over to the right one unit from the y-intercept. You should arrive at the point (1, 1)

Then, again from the y-intercept, go down two units and to the left one unit. You should arrive at the point (-1, -3)

Now draw a straight line through the y-intercept and the other two points you just found

The image of the graph is shown below

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0

3 years ago