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nikklg [1K]
4 years ago
10

What is 2+2+2-2-2+50-20+800-256+12?

Mathematics
2 answers:
victus00 [196]4 years ago
6 0

588

hope this helps :p

zalisa [80]4 years ago
4 0

2+2+2-2-2+50-20+800-256+12 = 588

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Vicki is 5 years older than twice Ella's age, a.
Anettt [7]

Answer:

5+3a=29

Step-by-step explanation:

let Ella's age be 'a'

Vicki's age=5+2a

sum of their ages= 29

So, the equation is

  (5+2a)+a=29

       5+3a=29

<em>hope this helps!</em>

8 0
3 years ago
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PLEASE HELP ME?! BRAINLIEST ANSWER PLUS EXTRA POINTS! The perimeter of a basketball court is 84 meters and he length is 6 meters
Marina86 [1]

Answer:

I hope this helps you and you have an amazing day the answer

Width=12

Length=30

Step-by-step explanation:

L=2W+6 is

P=2L+2W

84=2(2W+6)+2W

84=4W+12+2W

84=6W+12

6W=84-12

6W=72

W=72/6

W=12 ans. for the width.

L=2*12+6=24+6=30 ans. for the length.

Proof:

84=2*30+2*12

84=60+24

84=84

3 0
3 years ago
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Arnold takes 12 minutes to swim 10 lengths of a pool whose length is 50 meters. If he swims at a constant speed, how long does i
Phoenix [80]
It will take him 240 min and if u convert that it will take him 4 hours
5 0
3 years ago
I WILL MAKE YOU THE BRAINY IF YOU GET THE RIGHT ANSWER FIRST :D
Arte-miy333 [17]
A^2 - 6a/a-6 • a+3/a
a(a - 6)/(a - 6) • a+3/a
a • (a + 3)/a
a(a+3)/a
a+3.

The correct solution to this question would be B. a+3.
8 0
3 years ago
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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
4 years ago
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