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Andre45 [30]
2 years ago
9

Two times a number plus 3 equals one half of the number plus 30. What is the number please?

Mathematics
1 answer:
Zanzabum2 years ago
7 0

Answer:

Step-by-step explanation:

2*x + 3 = 1/2x + 30             Subtract 3 from both sides

<u>       - 3                -3</u>

2x = 1/2x + 27                     Subtract 1/2 x from both sides

<u>1/2 x  -1/2 x</u>

1 1/2 x = 27                         change 1 1/2 to 3/2

3/2 x = 27                           Multiply by 2/3

2/3 * 3/2x = 27 * 2/3

x = 18

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Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

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Answer:

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Step-by-step explanation:

that point is where the edge if the rectangle is

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Ulleksa [173]

Answer:

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Step-by-step explanation:

5 0
3 years ago
A new Community Sport complex is being built in safe harbor the perimeter of the rectangular playing field is 402 yards the leng
ivanzaharov [21]

Answer:

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Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

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l is the length

w is the width

From the question

Perimeter = 402 yards

The statement

the length of the field is 9 yards less than quadruple the width is written as

l = 4w - 9

Substitute this is expression into the above formula and solve for the width

That's

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Divide both sides by 10

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Substitute this value into l = 4w - 9

That's

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Therefore

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Hope this helps you

3 0
3 years ago
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