Sounds like a problem in binomial probability. What do you think?
Here the # of experiments is 6, so n = 6. The probability of a baby girl being born is 0.50.
Using my TI-83 Plus calculator:
binompdf(6, 0.5, 2) = 0.234
binompdf(6, 0.5, 3) = 0.313
binompdf(6, 0.5, 4) = 0.234
binompdf(6, 0.5, 5) = 0.094
binompdf(6, 0.5, 6) = 0.016
To get the prob. of at least 2 girls in 6 births, add up the 5 probabilities given above:
P(at least 2 girls in 6 births) = 0. ???
The answer of 453 divided by 8 is 56,625.
Answer:
2=x
Step-by-step explanation:
8(4-x)=7x+2
Distribute
32 - 8x = 7x+2
Add 8x to each side
32 - 8x+8x = 7x+8x+2
32 = 15x+2
Subtract 2 from each side
32-2 = 15x+2-2
30 = 15x
Divide each side by 15
30/15 = 15x/15
2 =x
D because -50x is the amount you’re subtracting from the total