PLEASE SOMEONE ANSWER MY QUESTION
Answer:
(0,0) and (7,10)
Step-by-step explanation:
recall that the slope - intercept form of a linear equation can be given as
y = mx + b
where m = slope and b = y intercept
in our case, we are given that slope, m = 10/7, hence our equation becomes
y = (10/7) x + b
since we are not given any information about the y-intercept, we can simply pick a value for b that is most convenient for us.
We pick b = 0, hence the equation simplifies to:
y = (10/7) x ----- eq 1
we can see immediately that if x = 0, y must also = 0
proof if x = 0:
y = (10/7)(0) =0
since 0 is an integer, then (0,0) must be the first point.
we can also observe that for y to be an integer, we must get rid of the denominator 7. We can do this by multiply the right side by 7. Hence we let x = 7:
y = (10/7) x 7
y = 10
hence (7,10) is the second point.
Answer:
x - 8y = - 56
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Given
y = 
x + 7
Multiply through by 8 to clear the fraction
8y = x + 56 ( subtract 8y from both sides )
0 = x - 8y + 56 ( subtract 56 from both sides )
- 56 = x - 8y, that is
x - 8y = - 56 ← in standard form
Answer:
Step-by-step explanation:
A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?
In this question it basically wants you to leave Y alone in a side of the equation.
In this case,
For 3y=c
For Ay=w
For Y/c=w
Y=cw
For y/a=2c
y=2ac
For a=y+p
y=a-p
For C=y-k
y=C+k
