Question

A ball is dropped from 248 feet above

Answer 1

Let us say

The Height from which the ball was first dropped as H0 = 248 feet

The Height reached by the ball after second bounce is H1

The Height reached by the ball after second bounce is H2 = 62 feet

Given , Height the ball reaches after bounce is a fraction of the height the ball reached in the previous bounce

The Height reached by the ball after second bounce = H2 = X of H1

==> 62 = X * H1 ...................Equation 1

The Height reached by the ball after first bounce = H1 = X of H0

==> H1 = X * 248 ...................Equation 2

Substituting value of H1 from Equation 2 to Equation 1

62 = X * H1 = X * X * 248

X^2 = 62/248 = 31/124 = 1/4

X = 1/2

Answer is A. 1/2

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