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2 years ago

Hi, please help me out with this math problem.

Mathematics

1 answer:

GalinKa [24]2 years ago

6 0

9514 1404 393

Answer:

x - 4

Step-by-step explanation:

The expression simplifies to ...

$\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|$

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

x - 4 . . . . for x ≥ 4

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2 years ago

What are the values of a 1 and r of the geometric series? 1 3 9 27 81.

sp2606 [1]

For the given geometric series the value of the common ratio(r) is 3, while the value of a₁ is 1.

<h3>What is geometric series?</h3>

A series of numbers whose any two consecutive numbers are always in a common ratio of that series.

Given to us

Series, 1 3 9 27 81

To find the value of the common ratio(r), we will simply find the ratio of any two consecutive numbers, therefore,

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Learn More about Geometric Series:

brainly.com/question/14320920

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