Question

Hi, please help me out with this math problem.

Answer 1

9514 1404 393

Answer:

  x - 4

Step-by-step explanation:

The expression simplifies to ...

  $\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|$

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

  x - 4 . . . . for x ≥ 4