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Darya [45]
3 years ago
13

itle="x - 1 = \sqrt{ \frac{y + 7}{2} } " alt="x - 1 = \sqrt{ \frac{y + 7}{2} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Anika [276]3 years ago
4 0
<h2>Solving for x:</h2><h2 />

x =   \sqrt{ \frac{y + 7}{2} }  + 1

<h3>Step-by-step explanation:</h3>

1) Just add 1 to both sides.

<h3 /><h2>Solving for y:</h2>

y = 2( {x}^{2}  - 2x + 1) - 7

<h3>Step by step explanation:</h3>

1) Square both sides.

{x}^{2}  - 2x + 1 =  \frac{y + 7}{2}

2) Multiply both sides by 2.

( {x}^{2}  - 2x + 1) \times 2 = y + 7

3) Regroup terms.

2( {x}^{2}  - 2x + 1) = y + 7

4) Subtract 7 from both sides.

2( {x}^{2}  - 2x + 1)   - 7  = y

5) Switch sides.

y = 2( {x}^{2}  - 2x + 1) - 7

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>Y</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u> </u></em><em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>x</u></em><em><u>²</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>2x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u> </u></em><em><u>-7</u></em><em><u>.</u></em>

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