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3 years ago

(sorry bout the other one I forgot to put the picture and it wouldn't let me delete)

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

I’m pretty sure it is.

Ivanshal [37]3 years ago

3 0

Answer:

The correct answer should be 5

Step-by-step explanation:

start at a point where the line passes through the vertex of the small grid box given and count how many units u need to go up and right to reach to the next point where the line passes in a similar way, since you need to find the rise, just count how many units u need to go up. The answer would be 5

Hope this helps!

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Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou

mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

$\frac{dQ}{dt} = -kQ$

In which k is the decay rate.

The solution is:

$Q(t) = Q(0)e^{-kt}$

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that $Q(0) = 8000$

500 counts per minute 13 days later.

This means that $Q(13) = 500$ . We use this to find k.

$Q(t) = Q(0)e^{-kt}$

$500 = 8000e^{-13k}$

$e^{-13k} = \frac{500}{8000}$

$\ln{e^{-13k}} = \ln{\frac{500}{8000}}$

$-13k = \ln{\frac{500}{8000}}$

$k = -\frac{\ln{\frac{500}{8000}}}{13}$

$k = 0.2133$

$Q(t) = Q(0)e^{-0.2133t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.2133t}$

$0.5Q(0) = Q(0)e^{-0.2133t}$

$e^{-0.2133t} = 0.5$

$\ln{e^{-0.2133t}} = \ln{0.5}$

$-0.2133t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.2133}$

$t = 3.25$

The half-life of the radioactive substance is of 3.25 days.

7 0

3 years ago

Help I need this ASAP I will mark brainliest!!

Mekhanik [1.2K]

Answer:

V= 7.5ft x 4.2 ft x w ft

Step-by-step explanation:

TO find the volume, you follow the expression. height x width x length.

7.5 x 4.2 = 31.5

Next we will use the substituted width of 2.

31.5 x 2 = 63 ft

I would like to say that you can multiply the height, width, and length in any order due to the commutative property.

7 0

3 years ago

Find the length of arc XPY.

KiRa [710]

Answer:

Arc length XPY =28.26 m.

Step-by-step explanation:

Given : A circle with two arc XY and XPY and radius 6 m.

To find : Arc length XPY.

Solution : We have given that arc XY and XPY .

Radius = 6 m.

Central angle formed by arc XPY = 360 - 90 = 270.

Arc length = 2 *pi* r ( $\frac{central\ angle}{360}$ .

Plugging the values

Arc length = 2 *3.14 * 6 ( $\frac{270}{360}$ .

Arc length =37.68 ( $\frac{3}{4}$ .

Arc length =37.68 * 0.75

Arc length XPY =28.26 m.

Therefore, Arc length XPY =28.26 m.

6 0

3 years ago

Read 2 more answers

3 divided by 1/2 please help me

rjkz [21]

Answer:

1.5

Step-by-step explanation: 3 divided by 1/2 is 1.5.

7 0

3 years ago

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Find the first four terms in the sequence an = 15 + 6n

Alona [7]

Answer:

21, 27, 33, 39 and so on....

6 0

3 years ago