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Artist 52 [7]
2 years ago
15

Which equation produces the values in the table? O y= 4x O y=4+x O y=1/4x Oy=4 - x

Mathematics
1 answer:
MakcuM [25]2 years ago
6 0

Answer:

Step-by-step explanation: It’s C thank me later

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A drawing of a basketball backboard was made using semicircle and rectangle
elena-14-01-66 [18.8K]
Answer:B 253.17
100% sure
8 0
2 years ago
How do you find the area of the field in <br> terms of x
Alex_Xolod [135]

Hello from MrBillDoesMath!


Answer:  104x^2 + 166x + 66

Discussion:

The area of a rectangle is given by "length" * "width". For us the formula becomes

 (13x + 11) * (8x+6)


or

13x (8x +6) + 11 * (8x + 6)  =


(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =

(104x^2 + 78x ) + (88x + 66) =

104x^2 + (78x + 88x) + 66 =


104x^2 + 166x + 66


Thank you,

MrB

4 0
3 years ago
I have no idea what this means
zhuklara [117]

Answer: idk the answer but i can tell u that u are trying to find the value of the symbols and the numbers :)

Step-by-step explanation:

5 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
2 years ago
When rolling a pair of dice at the Bellagio Casino in Las Vegas, there is 1 chance in 36 that the outcome is a 12.
nasty-shy [4]
Yes, that is correct. likewise, the odds of rolling a 1 are \frac{1}{36}
3 0
3 years ago
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