Answer:
Step-by-step explanation:
x^2 + 11y + y^2 -3x + 11 = 5x +23 - y
First put it into general form by setting the equation to zero and moving all variables to one side.
x^2 + 11y + y^2 -3x + 11 = 5x +23 - y
+y -5x -11 -11
x^2 + y^2 - 8x + 12y = 12
Then solve by completing the square
x^2 - 8x y^2 + 12y = 12
(x - )^2 + (y + )^2 =
Half of 8 is 4
Then square 4 to get 16
Therefore, we plug the 4 into the first parentheses
x^2 - 8x + 16 + y^2 + 12y =12 +16
(x - 4)^2 + (y + )^2 =
Half of 12 is 6
Squared, that would be 36
plug this into the second parentheses
x^2 - 8x + 16 + y^2 +12y + 36 = 12 + 16 + 36
(x - 4)^2 + (y + 6)^2 =
12 + 16 = 28 + 36 = 64
Therefore, the equation of the circle is: (x - 4)^2 + (y + 6)^2 = 64
Which is option D
