Answer:
Average rate of change uses the slope formula (AKA rise over run AKA change in y over change in x AKA y2-y1 over x2-x1). To find y2 and y1, plug the x-values from your interval end points into the function f(x). Say f(1) and f(a). i really hope that helps
Step-by-step explanation:
Answer:
Her commute would be between 32 and 35 minutes 33 times.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 28, \sigma = 4.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2028%2C%20%5Csigma%20%3D%204.5)
Proportion of days in which the commute is between 32 and 35 minutes:
This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 32.
X = 35
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{35 - 28}{4.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B35%20-%2028%7D%7B4.5%7D)
![Z = 1.555](https://tex.z-dn.net/?f=Z%20%3D%201.555)
has a pvalue of 0.94.
X = 32
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{32 - 28}{4.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B32%20-%2028%7D%7B4.5%7D)
![Z = 0.89](https://tex.z-dn.net/?f=Z%20%3D%200.89)
has a pvalue of 0.8133.
0.94 - 0.8133 = 0.1267
Out of 262 days:
Each day, 0.1267 probability
0.1267*262 = 33
Her commute would be between 32 and 35 minutes 33 times.
For an inscribed quadrilateral, opposite angles add up to 180 degrees. In this case, if we are looking for the measure of angle D, we can use the fact that angles I & D add up to 180 degrees. Since angle I = 117:
117 + D = 180
D = 63 degrees
Answer:
- ![\frac{9}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D)
Step-by-step explanation:
Step 1: Add the numerator fractions.
2/5 + 3/10
Here we have to find LCD, the LCD of 5 and 10 is 10
(2*2) + 3 4 + 3
Therefore, 2/5 + 3/10 = --------------- = ------------------
10 10
= 7/10
Step 2: Now substitute 2/5 + 3/10 = 7/10 in the given fraction, we get
7/10
= ----------
-7/9
If we have fraction over fraction, we have to find the reciprocal of denominator fraction and multiply.
The reciprocal of -7/9 is -9/7
Step 3: Now multiply 13/10 and -9/7
= (7/10) x (-9/7)
= -9/10
=-9/10
The answer is -![\frac{9}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D)