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3 years ago

8

Sara wrote 524 words in her journal. Then she crossed out 56 words and added 95 new words. How many words are written in her jou

rnal now?

1 answer:

Musya8 [376]3 years ago

7 0

You have 524 words then subtract by 56 bc she crossed them out and then she added 95 by writing them so therefor the answer is 563

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The difference of three times a number and eleven times it’s square. What’s this equation???

Naddik [55]

Answer:

(N represents a number)

((N^2)x11)-(3xN)

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3 years ago

The angle of elevation from a soccer ball on the ground to the ground to the top of the goal 34 degrees. If the goal is 8 ft tal

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Check the picture below.

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3 years ago

Read 2 more answers

A seal went 15 below sea level to catch a fish. A sea lion dove 6 feet less than two times as deep as the seal to catch a larger

anygoal [31]

Answer:

$2\times 15-6 = 24\ below\ sea\ level$

Step-by-step explanation:

Given that:

Distance traveled by seal to catch the fish = 15 below sea level

Sea lion wanted to catch a larger fish so sea lion dove 6 feet lesser than two time the distance that the seal traveled.

To find:

The expression to represent the position of the sea lion in the sea.

Solution:

If the distance traveled by seal is represented by $D$ then as per the question statement:

Twice of $D$ = $2\times D$

6 lesser than twice of $D$ = $2\times D$ - 6

Now, putting the value of $D$ = 15

Therefore, the expression to represent the sea lion's position w.r.to sea level.

$2\times 15-6\\ = 24\ below\ sea\ level$

5 0

3 years ago

Twelve increased by a number

pochemuha

Answer:

12+# OR 12+x

Step-by-step explanation:

Increased by 12 means plus 12. The word "is" in equations is an equal sign. So far, you have 2n+12. On the other side of the equal sign, you have 31 less than 3 times a number.

3 0

3 years ago

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

3 years ago