Answer:
as 18/5 =3.6
so we need minimum 4 bags of chips
Answer:
0.6672 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 8.4 minutes
Standard Deviation, σ = 3.5 minutes
We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.
According to central limit theorem the sum measurement of n is normal with mean
and standard deviation 
Sample size, n = 37
Standard Deviation =

P(taxi and takeoff time will be less than 320 minutes)

Calculation the value from standard normal z table, we have,

0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
4.5/9. It is technically an improper fraction but it still counts.
So (f-g)(x) = 3x2 + x, so when x = 2, the function is 14
The equation has no solution because:
5(n+10)=5n+10n
5n+10n=5n+10n
I subtract 5n from both sides
10n=10n
Only one side is supposed to have the variable which is n, so the equation has no solution.