If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.
We are required to find the approximate margin of error.
Margin of error is the difference between calculated values and real values.
n=1488
p=0.69
Margin of error=z*
Z score when confidence level is 99%=2.576.
Margin of error=2.576*
=2.576*
=2.576*
=2.576*
=2.576*0.01198
=0.03088
Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Learn more about margin of error at brainly.com/question/10218601
#SPJ1
Answer:
a. 120/w = l
120/l = w
b. l times w = 120
Step-by-step explanation:
Answer:
0.5
Step-by-step explanation:
I found this out because I am smart
In this problem, the power of 10 is 14. Hope this helps!
Answer:
n(A)= 10
Step-by-step explanation:
Hope it is ..mark me as brilliant