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Airida [17]
3 years ago
13

Pls help fast I want to see light soon!!!

Mathematics
2 answers:
inysia [295]3 years ago
3 0

Answer:

7.2

Step-by-step explanation:

7.4 - 0.2 = 7.2

<em>PLEASE DO</em><em> </em><em>MARK ME</em><em> </em><em>AS BRAINLIEST</em><em> </em><em>IF MY</em><em> </em><em>ANSWER IS</em><em> </em><em>HELPFUL</em><em> </em><em>:</em><em>)</em><em> </em>

fgiga [73]3 years ago
3 0

Answer: Its going to be 7.2

Step-by-step explanation:

All you have to do is put the problem into a calculator and it solves it for you.

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Write this number in standard notation.
Gnom [1K]

Answer:

12345678910

Step-by-step explanation:

TANQR

5 0
2 years ago
2. A certain TV can be purchased from the manufacturer for $160. A certain online retailer has a standard markup of 30%, and a c
Vanyuwa [196]
Price, when purchased online:  1.30($160)
Price, when purchased at superstore:  1.40($160)

Difference in prices:  1.40($160) - 1.30($160) = 0.10($160) = $16

A higher markup brings a higher retail price.
8 0
3 years ago
A 15 kilogram object is suspended from the end of a vertically hanging spring stretches the spring 1/3 meters. At time t = 0, th
Yuri [45]

Answer:

15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

y(0)=0, y'(0)=0

Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

k = \frac{F_{r}}{y} = \frac{mg}{y} = \frac{15 Kg (9.81 \frac{m}{s^{2} } )}{\frac{1}{3} m}  = 441.45 \frac{N}{m}

Now we apply Newton's 2nd Law and obtaint that...

F_{r} (t) ± F(t) = ma(t)

F_{r} (t) = ky(t) = 441.45y(t)

F(t) = 170 cos(5t)

m = 15 kg

a(t) = \frac{d^{2}y(t)}{dt^{2} }

Finally... 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

6 0
3 years ago
I need help with the questions in the pictures
Inessa [10]
Oh geez they poor lol
6 0
3 years ago
The diagram shows a square pyramid over a cube. What is the volume of the entire figure?
TEA [102]

Answer: 810

Step-by-step explanation:

first lets take down the information we were given,

height (h) of the pyramid should be 12 - 9 = 3

base (a) = 9

So we calculate the volume of a square pyramid

V = a²h/3

V = (9² × 3) / 3

v = (81 × 3) / 3

V = 81

now we calculate the volume of the cube using the formula

V = a³

V = 9³

V = 729

NOW to get the volume of the entire figure

we say

volume of square pyramid + volume of cube

81 + 729 = 810

3 0
3 years ago
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