Question

Message

Answer 1

Answer:

Part A

x + y ≤ 460

2.5·x + 1.25·y ≥ 600

Part B

192 bottles

Step-by-step explanation:

The given parameters are;

The selling price of a can of lemonade = $2.50

The selling price for each bottle of water = $1.25

The amount the club needs to raise to cover the cost of renting costumes, A = $600

The maximum acceptable cans and bottles = 460

Part A

Let 'x', represent the number of cans of lemonade accepted by the students, and let 'y' represent the number of bottles of water accepted, we have;

The situation can be represented by the following system of inequalities

x + y ≤ 460

2.5·x + 1.25·y ≥ 600

Part B

The number of cans of lemonade sold, x = 144

Therefore, we have;

2.5 × 144 + 1.25·y ≥ 600

1.25·y ≥ 600 - 2.5 × 144 = 240

1.25·y ≥ 240

y ≥ 240/1.25 = 192

y ≥ 192

The least number of bottles of water that must be sold to cover the cost of renting costumes, y = 192 bottles