Answer:
Part A
x + y ≤ 460
2.5·x + 1.25·y ≥ 600
Part B
192 bottles
Step-by-step explanation:
The given parameters are;
The selling price of a can of lemonade = $2.50
The selling price for each bottle of water = $1.25
The amount the club needs to raise to cover the cost of renting costumes, A = $600
The maximum acceptable cans and bottles = 460
Part A
Let 'x', represent the number of cans of lemonade accepted by the students, and let 'y' represent the number of bottles of water accepted, we have;
The situation can be represented by the following system of inequalities
x + y ≤ 460
2.5·x + 1.25·y ≥ 600
Part B
The number of cans of lemonade sold, x = 144
Therefore, we have;
2.5 × 144 + 1.25·y ≥ 600
1.25·y ≥ 600 - 2.5 × 144 = 240
1.25·y ≥ 240
y ≥ 240/1.25 = 192
y ≥ 192
The least number of bottles of water that must be sold to cover the cost of renting costumes, y = 192 bottles
