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Ludmilka [50]
2 years ago
15

Find the product (-3/5) (-2/9)

Mathematics
2 answers:
Temka [501]2 years ago
8 0
I think the answer is 2/15
bija089 [108]2 years ago
6 0

Answer:

2/15

Step-by-step explanation:

(-3/5) (-2/9)

Rewriting

-3/9 * -2/5

-1/3 * -2/5

A negative times a negative is a positive.

2/15

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In a café, I order a cup of tea and a piece of cake and it costs £1.10. The next time I order 2 cups of tea and one piece of cak
defon

Answer:

£0.50

Step-by-step explanation:

t = one cup of tea

c = one piece of cake

t + c = £1.10

2t + c = £1.70

the cost increases by £0.60 (£1.70 - £1.10) when you order one more cup of tea which means that one cup of tea costs £0.60

substitute £0.60 into t + c = £1.10

£0.60 + c = £1.10

rearrange to get c = £1.10 - £0.60 = £0.50

so one piece of cake costs £0.50

7 0
3 years ago
Read 2 more answers
Find the area<br><br> A. 50in<br> B. 60in<br> C. 50in2<br> D. 60in2
ludmilkaskok [199]

Answer:

The answer is 60in^2

Step-by-step explanation:

5 0
3 years ago
Two horses are ready to return to their barn after a long workout session at the track. The horses are at coordinates H(1,10) an
lana [24]
Distance between points \left(x_1,y_1\right) and \left( x_2,y_2 \right) is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Distance from H to B:

[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.

Distance from Z to B:

d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269} units.

Horse Z is closer to the barn.

(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)
6 0
3 years ago
Answer this maths watch question step-by-step
Scilla [17]

The value of <u>a</u> is 2 and the value of <u>b</u> is 6.

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

You should factor the given expression.

2-\frac{x+3}{x+1}-\frac{x-5}{x-1}\\ \\ 2+\frac{-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \mathrm{Apply\:the\:fraction\:rule}:\quad \:a+\frac{b}{c}=\frac{ac+b}{c}\\ \\ \frac{2\left(x+1\right)\left(x-1\right)-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \frac{2x+6}{\left(x+1\right)\left(x-1\right)}=\frac{2x+6}{x^2-1}

Read more about the factoring here:

brainly.com/question/11579257

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4 0
2 years ago
AABC has vertices A(-4, 4), B(-1,2), and C(-4,1). What are the coordinates of
steposvetlana [31]

Answer:

(1, - 3 )

Step-by-step explanation:

Using the translation rule (x, y ) → (x + 2, y + 1 ), then

B(- 1, 2 ) → (- 1 + 2, 2 + 1) → (1, 3 )

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

(1, 3 ) → (1, - 3 )

6 0
3 years ago
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