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rodikova [14]
3 years ago
7

Harry worked 7 hours last week. This is 1/3 as many as Aidan worked. How many hours did Aidan work?

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0
Aidan has put 21 hours of work. To simplify it, Harry worked 7 hours and Aidan worked 7 x 3 times which equates to 21 hours.
Andreyy893 years ago
6 0

Answer:

Step-by-step explanation:

Exactly what he or she said

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2 years ago
Factor: k^2 + 7x + 10<br> A:(k+10)(k+4)<br> B:(k+2)(k+5)<br> C:(k+2)(k-5)<br> D:(k-2)(k-5)
Nata [24]

Answer:

the answer is B. (k+2)(k+5)

7 0
3 years ago
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Two groups collect litter along the side of a rode. It takes each group 5 min to clean up a 200-yard section. How long does it t
abruzzese [7]
The answer is 1 hr 28 min. picture included for work. there are other ways to solve this

6 0
3 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
3 years ago
Write an equation that gives the proportional relationship of the graph.
labwork [276]

Answer:

C

Step-by-step explanation:

A proportional graph is a line. Every line has a slope. The slope is found by subtracting two points as a ratio. The line has points (0,0) and (2,6).

6-0 = 6

2 -0 = 2

The ratio is vertical over horizontal so 6/2 = 3.

The equation is y = 3x.

8 0
3 years ago
Read 2 more answers
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