We can use the combined gas law equation to find the new pressure of the gas.
![\frac{P1V1}{T1} = \frac{P2V2}{T2}](https://tex.z-dn.net/?f=%20%5Cfrac%7BP1V1%7D%7BT1%7D%20%3D%20%20%5Cfrac%7BP2V2%7D%7BT2%7D%20%20)
where P - pressure
V - volume
T - temperature
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
P1 - 795 mm Hg x 0.0013 atm/ mm Hg = 1.033 atm
T1 - 23.5 °C + 273 = 296.5 K
T2 - 31.7 °C + 273 = 304.7 K
substituting the values in the equation
![\frac{1.033 atm *642 mL}{296.5K}= \frac{P*957mL}{304.7K}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1.033%20atm%20%2A642%20mL%7D%7B296.5K%7D%3D%20%20%20%5Cfrac%7BP%2A957mL%7D%7B304.7K%7D%20)
P = 0.712 atm
the answer closest to this value is A) 0.723 atm
therefore answer is
<span>A) 0.723 atm</span>
Explanation:
The maganese dioxide molecular formula by criss cross method is MnO2
I cannot answer this question exactly if the choices are not given. There is obviously more to this question. However, I can still give an idea about the vapor pressure of water and acetone. Acetone is a liquid ketone. It is more volatile compared to water. Therefore, you will expect acetone to have a lower vapor pressure than water. With the same conditions and same amount of initial volume, at a certain amount of time, the amount of liquid left in the container for water than acetone. This is because most of the acetone has already vaporized.