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Sladkaya [172]
3 years ago
15

[07.03] what is the ph of a 6.40 × 10-3 m solution of sodium hydroxide, naoh?

Chemistry
1 answer:
Katena32 [7]3 years ago
6 0
POH = - log [OH] 
<span>pOH = - log (6.40 × 10-3) </span>
<span>pOH = 2.19 </span>

<span>pH + pOH = 14 </span>

<span>pH = 14 - pOH </span>
<span>pH = 14 - 2.19 </span>
<span>pH = 11.8</span>
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