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Alex73 [517]
3 years ago
5

Find the area of the octagon with the length of one side 4in in the apothem of 7 in

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

28

Step-by-step explanation:

Just multiple, the 4 with the 7 and you'll get 28in

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It’s d because 12-15%=10.20
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2 years ago
Expand and simplify 4 ( y + 6 ) − 2 ( y − 2 )
elena-14-01-66 [18.8K]

[ Answer ]

\boxed{2y \ + \ 28}

[ Explanation ]

4(y + 6) - 2(y - 2)

[Expand] 4(y + 6): 4y + 24

4y + 24 - 2(y - 2)

[Expand] -2(y - 2): -2y + 4

4y + 24 - 2y + 4

[Simplify] 4y + 24 - 2y + 4: 2y + 28

= 2y + 28

\boxed{[ \ Eclipsed \ ]}

7 0
3 years ago
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3.) Duncan spent $70 and now has<br> $120. How much money did he have<br> before spending the 70?
frosja888 [35]

Answer:

He started with $190

7 0
3 years ago
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Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

\frac{10}{100}*80,000,000+80,000,000

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

\frac{10}{100}*88,000,000+88,000,000

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

<em>or simply subtract the number of cars in year 2 from that in year 3;</em>

96,800,000-88,000,000 = 8,800,000

8 0
3 years ago
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Tap on the thing and somebody help me with all this pls
Mumz [18]
Hey what number do you need help with
8 0
3 years ago
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