For this case we have the following table:
x f(x)
<span><span><span>0 2
</span><span>1 5
</span><span>2 10
</span><span>3 17
</span></span></span> The equation that best fits the data in the table, for this case, is given by a quadratic function.
<span><span><span> </span></span></span>The quadratic function in its standard form is:
f (x) = x2 + 2x + 2
Answer:
f (x) = x2 + 2x + 2
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14 boys : 16 girls
but this would have to be simplified also
7:8
Answer:
Okay so I am not positive but I will try to help you out. Okay so the line of best fit would positive. Because it is all going up. The approximate slope is 3/4 Because slope is change in y over change in x. The y intercept of the line of best fit would be (0,0). This is because when drawing the line you can see that it would intercept the y-axis at zero. My steps taken were basically just looking at it and peicing everything together. If you want to get more involved with slope you could pick to coordinates which I will include and do change in y over change in x.
My points I will pick are (1,1) and (5,2)
2-1/5-1=3/4
therefore approximate slope is 3/4
Like I said I am not positive but I am just trying to help out in some way.
If something is incorrect please inform me. If this helps also please inform me.
Answer:
1, 5 and 6.
Step-by-step explanation:
The sides of this triangles has lengths in the ratio x : √3x : 2x where 2x is the hypotenuse.
When C = 30, the side AB is the small leg (=x).
When B = 90, the hypotenuse is AC ( =2x).
When A = 60, the larger leg is BC (=√3x).
1. AB = 4, BC = 4√3 :- Are possible legs.
5 AB = 7, AC = 14. :- AB = small leg, AC = hypotenuse.
6. AB = 11, BC = 11√3:- AB = small, BC = larger leg.
