The height of the object at the time of launch is 100 meters.
To find this, we simply have to put 0 in for x, as this is when there has been no time (at launch)
h(x)=-5(x-4)^2+180
h(0)=-5(0-4)^2+180
h(0)=-5(-4)^2+180
h(0)=-5(16)+180
h(0)=-80+180
h(0) = 100
Answer:
the answer is D hope this helps
Step-by-step explanation:
This answer is 135.
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