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Nadusha1986 [10]
3 years ago
13

A car travels along a straight stretch of road. It proceeds for 16.2 mi at 57 mi/h, then 24.6 mi at 44 mi/h, and finally 45.1 mi

at 37.8 mi/h. What is the car’s average velocity during the entire trip? Answer in units of mi/h.
Mathematics
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

The average velocity the entire trip was 43.25 mi/h

Step-by-step explanation:

In this case we have to calculate an average based on the miles traveled. First we have to calculate the total of miles traveled, then calculate the portion of the total travel of each and with this calculate the average speed during the trip. First the total miles traveled:

TotalMiles=16.2+24.6+45.1=85.9

Now the percentages:

At 57 mi/h were \frac{16.2}{85.9}=0.19

At 44 mi/h were \frac{24.6}{85.9}=0.29

At 37.8 mi/h were \frac{45.1}{85.9}=0.52

Now multiplying the speed by the portion and summing them we can have the average velocity:

57*0.19+44*0.29+37.8*0.52=43.25

The average velocity the entire trip was 43.25 mi/h

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Papessa [141]

Using it's formula, the average rates of change are given as follows:

a) 30 meters per second.

b) -10 meters per second.

<h3>What is the average rate of change of a function?</h3>

The average rate of change of a function is given by the <u>change in the output divided by the change in the input.</u> Hence, over an interval [a,b], the rate is given by the following equation:

r = \frac{f(b) - f(a)}{b - a}

For item a, taking the data from the table, we have that:

  • f(0) = 0.
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Hence the rate is given as follows:

r = (138 - 0)/(4.6 - 0) = 30 meters per second.

For item b, taking the data from the table, we have that:

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Hence the rate is given as follows:

r = (0 - 23)/(11.5 - 9.2) = -10 meters per second.

More can be learned about the average rate of change of a function at brainly.com/question/11627203

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1 year ago
HELP PLEASE!!!!!!!!!!!!
Bogdan [553]

Answer:

See the explanation.

Step-by-step explanation:

We are given the function f(x) = x² + 2x - 5

Zeros :

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The left hand side can not be factorized. Hence, use Sridhar Acharya formula and  

x= \frac{-2+\sqrt{2^{2}-4\times(-5)\times1 } }{2} and  

x= \frac{-2-\sqrt{2^{2}-4\times(-5)\times1 } }{2}

⇒ x = -3.45 and 1.45

Y- intercept :

Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.

Maximum point :

Not defined

Minimum point:  

The equation can be expressed as (x + 1)² = (y + 5)

This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis

Therefore, the minimum point is (-1,-5)

Domain :  

x can be any real number

Range:  

f(x) ≥ - 6

Interval of increase:

Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.

Therefore, interval of increase is +∞ > x > -1

Interval of decrease:

-∞ < x < -1

End behavior :  

f(x) = x^{2} +2x-5 =x^{2}  (1+\frac{2}{x} -\frac{5}{x^{2} } )

So, as x tends to +∞ , then f(x) tends to +∞

And as x tends to -∞, then f(x) tends to +∞. (Answer)

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