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cestrela7 [59]
3 years ago
9

Create a BOX PLOT with this data set by using the Jamboard attached to this assignment... 3, 1, 3, 7, 5, 2, 3, 6, 3

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

Step-by-step explanation:

in order to make a box plot you need to know 5 things.

the minimum, the first quartile, the median, the third quartile, and the maximum value. aka <em>the five number summary </em>

using your calculator you can find that in this set of values:

min = 1

Q1 = 2.5

med (Q2) = 3

Q3 = 5.5

max = 7

the box plot will look something like this:

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Explanation:
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Add both answer together to get 93750 and divide it by 6
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EASYY TO ANSWER I WILL MARK YOU AS BRILIANT HELP PLEASE
BARSIC [14]

Question 1: (0,2) because b value in mx+b is y-intercept


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Question 3: plug in -4 for x you will get -5 so min is (-4, -5)


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3 years ago
Jasmine drew triangles on a globe and on a flat map of the world, as shown below.Which is a true statement comparing Jasmine’s t
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3 years ago
Use linear approximation to approximate 25.3‾‾‾‾√ as follows. Let f(x)=x√. The equation of the tangent line to f(x) at x=25 can
loris [4]

Answer:

Approximation f(25.3)=5.03 (real value=5.0299)

The approximation can be written as f(x)=0.1x+2.5

Step-by-step explanation:

We have to approximate f(25.3)=\sqrt{25.3} with a linear function.

To approximate a function, we can use the Taylor series.

f(x)=\sum_1^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n

The point a should be a point where the value of f(a) is known or easy to calculate.

In this case, the appropiate value for a is a=25.

Then we calculate the Taylor series with a number of terms needed to make a linear estimation.

f(x)\approx f(a)+\frac{f'(a)}{1!}(x-a)

The value of f'(a) needs the first derivate:

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Then

f(x)\approx f(25)+\frac{1}{10}(x-25)=\sqrt{25} +\frac{1}{10}(x-25)\\\\f(x)\approx 5+\frac{1}{10}(x-25)

We evaluate for x=25.3

f(25.3)\approx 5+\frac{1}{10}(25.3-25)\\\\f(25.3)\approx 5+\frac{1}{10}(0.3)=5.03

If we rearrange the approximation to be in the form mx+b we have:

f(x)\approx 5+\frac{1}{10}(x-25)=5+0.1x-2.5\\\\f(x)\approx 0.1x+2.5

Then, m=0.1 and b=2.5.

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