
so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well, you know, if we end up with a 0 at the denominator, like

then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.
so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".
Answer:
As we get closer to x=-3, the limit is approaches -1, on both sides of -3 so this is a good limit so c is 8.
Step-by-step explanation:
In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.
In this case, this a piece wise function and by definition of a limit that exist, the limit of this piece wise function as x approaches 3 from either side, must be equal.
We let x=-3 for the top equation.

So we set the second equation equal to -1.




So the value of c is 8. We can prove this by graphing as well.
Answer:
what he said ig
Step-by-step explanation:
just check it out
Answer: Perimeter = 2(L + W) and
as a simplified expression is, 8x + 2
Step-by-step explanation: The length is represented by L and the width is represented by W in the expression above.
However, since we have been given the sides of the rectangle as x + 2 and 3x - 1, we shall substitute for the values of these in the expression representing the perimeter.
2(L + W) can now be written as
2( {x + 2} + {3x - 1} )
2(x + 2 + 3x - 1)
By collecting like terms, we now have
2(4x + 1)
8x + 2.
The expression can now be simplified as 8x + 2