What is the value of d when f(x)=8

15 + 3t - 5 - 8t what is the ANSWER to this

Vikki [24]

15+3t−5−8t=15+3t+−5+−8tCombine Like Terms:=15+3t+−5+−8t=(3t+−8t)+(15+−5)=−5t+10Answer:=−5t+10

8 0

3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

3 years ago

Why did delegates argue over representation in congress?

KatRina [158]

They argued because they didnt agree over the congresses conclusion they made with the delegates.

5 0

3 years ago

Last month, a manufacturing company shipped 452 boxes of ball bearings.Each box contains 48 balls bearings. How many ball bearin

Arturiano [62]

Answer: the company shipped 21,696 ball bearings.

Step-by-step explanation:

Each box contains 48 balls bearings and the company shipped 452 boxes, so it is a simple multiplication 452 times 48 = 21,696

6 0

3 years ago

Read 2 more answers

Help me asap thanks ! :)

pychu [463]

Answer 145°

Step-by-step explanation:

( 5x+5 ) + 40° = 15x - 5

[ Reason : exterior extended angle of a triangle is always equal to the sum of two non adjacent interior angles ]

( 5x+5 ) + 40° = 15x - 5

i.e, x= 10°

put this value of x on <PGF

= 15x - 5

= 15 * 10 - 5

=145°

6 0

3 years ago