All categories

2 years ago

The product of b and 7

Mathematics

1 answer:

pshichka [43]2 years ago

4 0

Answer:

i need help with my math homework someone please help mee

Step-by-step explanation:

You might be interested in

What addition doubles fact can help you find 4+3

PtichkaEL [24]

The answer would be 7

8 0

3 years ago

Find the length of OC.

frosja888 [35]

Answer:

About 8

Step-by-step explanation:

I found this by doing 16 divided by 2 since half of 16 is 8and AC and OC are congruent so I think it is 8.

6 0

3 years ago

Read 2 more answers

A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart

Brums [2.3K]

Answer:

$1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}$

Step-by-step explanation:

The combined distance that both planes will cover is 200 miles

Time taken by both planes will be the same (t)

$\text{Distance}=\text{Speed}\times \text{Time}$

So, the combined distance is

$40t+100t=200\\\Rightarrow 140t=200\\\Rightarrow t=\dfrac{200}{140}\\\Rightarrow t=1.42\ \text{hours}=1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}$

They will meet in $1\ \text{hour}\ 25\ \text{minutes and }12\ \text{seconds}$ .

7 0

2 years ago

Read 2 more answers

What is the solution set of x2 + 5x + 1 = 0?

DerKrebs [107]

Answer:

$\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}$

Step-by-step explanation:

$x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}$

$\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}$

3 0

3 years ago

$2,000 IN AN ACCOUNT THAT PAID 6.25% SIMPLE INTEREST ANNUALLY

valkas [14]

$\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$2000\\
r=rate\to 6.25\%\to \frac{6.25}{100}\to &0.0625\\
t=years\to &3
\end{cases}
\\\\\\
A=2000(1+0.0625\cdot 3)\implies A=2000(1.1875)$

8 0

3 years ago