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Zina [86]
2 years ago
15

Work out p if r =3 and t=4 P=2r+3t

Mathematics
1 answer:
postnew [5]2 years ago
4 0
P=18 because 3 times two is 6 and 4 times 3 is 12 so when you add them you get 18
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Answer:

You convert the fractions to a decimal, nut the rest is still the same

Step-by-step explanation:

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Help pleaseeee!!!! Geometry
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Tan x=opposite/adjacent
cot x=adjacent/opposite

so you need to inverse the fraction
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What is the mean for the data set?
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Just add up all the numbers and divide by 6, as there are six numbers in this set of numbers
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Read 2 more answers
Find the slope intercept form of slope-2 which passes through (-5,1)
dusya [7]

Answer:

y=2x+11

Step-by-step explanation:

So we know that the slope is 2 and the lines passes through the point (-5,1).

We can use the point-slope form. The point-slope form is:

y-y_1=m(x-x_1)

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So, let's substitute 2 for m and (-5,1) for (x₁, y₁), respectively. Therefore:

y-(1)=2(x-(-5))

Simplify:

y-1=2(x+5)

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y-1=2x+10

Add 1 to both sides:

y=2x+11

So, the equation of our line is:

y=2x+11

6 0
2 years ago
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
<span>
</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
</span>
8 0
3 years ago
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