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Zina [86]
3 years ago
15

Work out p if r =3 and t=4 P=2r+3t

Mathematics
1 answer:
postnew [5]3 years ago
4 0
P=18 because 3 times two is 6 and 4 times 3 is 12 so when you add them you get 18
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PROVE THAT:<br><br>cos 20° - sin 20° = ​​ \sqrt{2}sin25°<br><br>​
Lemur [1.5K]

Answer:

See below.

Step-by-step explanation:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

First, use the co-function identity:

\sin(90-x)=\cos(x)

We can turn the second term into cosine:

\sin(20)=\sin(90-70)=\cos(70)

Substitute:

\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Now, use the sum to product formulas. We will use the following:

\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})

Substitute:

\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70)  =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)

Use the even-odd identity:

\sin(-x)=-\sin(x)

Therefore:

\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Replace the second term with the original term:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

Proof complete.

4 0
4 years ago
(6) Find a and b as well as the ratio c:d in the<br> figure below.
polet [3.4K]

Answer:

i have a Similar question I’m stuck on, just remember z rule, vertically opposite etc.

6 0
3 years ago
What is m∠BAC.<br><br> ............
gizmo_the_mogwai [7]

Answer:

37 degrees

Step-by-step explanation:

1. m∠CBA = 71+45 = 116 degrees

2. m∠CBA = m∠CDA because of the quadrilateral property of opposite sides.

3. m∠CBA + m∠CDA = 2*116 = 232.

4. Total angle measure of a quadrilateral is 360 degrees, so m∠BAD + m∠BCD = 360-232 = 128 degrees.

5. m∠BAD = m∠BCD = 128/2 = 64 degrees

6. m∠BAC = m∠BAD - m∠CAD = 64 - 27 = 37 degrees

8 0
3 years ago
In 1-4, match each scatter plot to the equation that could represent the equation of its trend line.
Leni [432]

Answer:

Step-by-step explanation

It is y=4x-2

3 0
3 years ago
Read 2 more answers
Find the h.c.f of {x}^{3} + {y}^{3} \: and \: \: {x}^{2} - xy + {y}^{2}x 3 +y 3 andx 2 −xy+y 2 ​
Ahat [919]

Factorize the sum of cubes:

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so x^2-xy+y^2 is a factor of x^3+y^3. Then the HCF is \boxed{x^2 - xy + y^2}.

5 0
2 years ago
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