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Bad White [126]
2 years ago
14

How many significant figures does the following number have: 0. 0 0 2 0 4 0

Mathematics
1 answer:
madreJ [45]2 years ago
5 0

Answer:

Four significant figures

Step-by-step explanation:

Rules of significant figure:

1. Zeros before any non-zero digit are considered to be NON-significant.

2. Any zeros between any non-zero digits are SIGNIFICANT

0.505

Here, there are three significant digits: 505

3. Any zeros that are to the right of the decimal point and a non-zero number are SIGNIFICANT.

4.0000

4. All non - zero digit are significant

Therefore,

0.002040 has four significant figures

2040

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Answer:

73

Step-by-step explanation:

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73 is the answer if that the question

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Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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yaroslaw [1]
39° or B that should be it
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Yes it does have to be parallel or else it would not be a rectangle.So it is true.

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