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RideAnS [48]
2 years ago
7

Can y’all HELPPPP MEEEEEEE PLEASEEEEE

Mathematics
2 answers:
tekilochka [14]2 years ago
5 0

Answer:

the 2nd one

Step-by-step explanation:

Nana76 [90]2 years ago
3 0

Answer:

The answer is the second one

Step-by-step explanation:

Like and give 5 star rating

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Determine whether the lines are parallel or perpendicular or neither. 2x=y−10 and y=−2x
MrRa [10]

Put the first equation in slope-intercept form, or y = mx + b. Start by subtracting y from both sides.

2x - y = -10, subtract 2x from both sides.

-y = -10 - 2x

Divide both sides by negative one.

y = 10 + 2x

To find the slope when the equations are in slope-intercept form you look at the coefficient of x. The first equation has the slope of 2 (which we just found), and the second equation has the slope of -2.

Parallel lines have the same slope and perpendicular lines have opposite reciprocal slopes. Since 2 and -2 are neither of these, your answer is neither.

7 0
3 years ago
I really dont get it what does it mean
svetoff [14.1K]
So basically what this is trying to tell you is are they mutiples / equal to each other, also a rule. Its A. because 25 x 2 = 50, then 50 x 2 = 100 and so on.

So the answer is A

Hope it helps! :D
4 0
3 years ago
Read 2 more answers
What is 0.000268 written in scientific notation?
Marina86 [1]
<span> 0.000268 = 2.68 x 10^-4

........................................</span>
7 0
3 years ago
Read 2 more answers
Jacob's favorite movie is 1 5/6 hours long. He says he has watch the movie 5 and a half times. If that is true. How many hours h
34kurt
1\frac{5}{6}=\frac{11}{6}, and when you multiply it by 5 it turns into \frac{55}{6}, which is 9\frac{1}{6}

So in conclusion he watched 9 & 10 minutes watching the movie
3 0
3 years ago
The following graph shows the distance Thomas is from his home (in meters) for a period of 2 minutes. Determine the average rate
irga5000 [103]
The answer:
<span>the average rate of change for the first 50 seconds:
it  is v= 100 m/ 50 s = 2 m/s
</span><span>Thomas speed is 2 m in each second for the first 50 seconds.

</span><span>The average rate of change for the 70 remaining seconds:
the time is between [70; 120]
so the distance is d= 200m - 40m= 160m
the average rate is
v= 160m / 70 s = 2 . 28m /s

</span>
6 0
3 years ago
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