Answer: m∠ABF = 120°
Concept:
Here, we need to know the idea of the <u>corresponding angle theorem </u>and <u>linear pair postulate</u>.
The corresponding angle theorem states that if a transversal cuts two parallel lines, their corresponding angles are congruent.
The linear pair postulate states that two angles that form a linear pair are supplementary.
Solve:
<u>Given information</u>
m∠ABF = m∠ABF = 2x + 3x
- According to the corresponding angle theorem, ∠ABF is congruent to ∠BCI which is 2x + 4x.
m∠BCH = 3x
Total angle = 180°
- ∠ABF and ∠BCH are linear pairs which means they form a supplementary angle.
<u>Given equation</u>
m∠ABF + m∠BCH = Total Angle
<u>Substitute values into the equation</u>
2x + 4x + 3x = 180
<u />
<u>Combine like terms</u>
9x = 180
<u>Divide 9 on both sides</u>
9x / 9 = 180 / 9
x = 20
m∠ABF = 2x + 4x = 2 (20) + 4 (20) = 40 + 80 = <u>120°</u>
Hope this helps!! :)
Please let me know if you have any questions
(5x-7)2 + 140x
= 25x2 - 70x + 14 + 140x
= 25x2 + 70x + 14
= (5x+7)2
D, because the Pythagorean theorem can only be used in the case of a right-angled triangle
The edge length that can be found is 6 cm
The block will not fit in the square hole.
<h3>How to find the volume of a cube?</h3>
We are given that the volume of a cube-shaped block is 216 cubic centimeters.
Thus;
V = 216 cubic centimeters.
Now, volume of a cube = a³
where x is an edge length
Thus;
a³ = 216
a = ∛216
a = 6 cm
The edge length that can be found is 6 cm
b) To know if the block will fit into the square hole, we need to find the area of one side of the block
Area of one side of block = 6 * 6 = 36 cm²
This is greater than the area of the square hole and as such the block will not fit in the square hole
Read more about Volume of a cube at; brainly.com/question/1882850
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Answer and step-by-step explanation:
starting at ground level means the helicopter starts at the bottom, works its way up to a cruse, then drops to ground level then goes to the top of a building meaning it would look up-and-down like
this graph should be the one you're looking for
hope this helps:)