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Dmitriy789 [7]
4 years ago
9

Find (-9/10)+22/15+13/-20

Mathematics
1 answer:
Zina [86]4 years ago
6 0
Answer:

-1/12 or -0.083333

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Lauren would like to find the midpoint of a line segment that has endpoints at (–0.5, 3) and (4, 7.5). Which statements are true
Bond [772]

Answer:

Lauren could solve 7.5 + 3 / 2 to find the y-intercept.

Lauren could solve (1/2)(4+0.5) to find the x-intercept.

Finding the midpoint is equivalent to partitioning a line segment a 1:1 ratio.

Step-by-step explanation:


7 0
4 years ago
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Can someone help me out here and the tell me the greatest common factor
EleoNora [17]

(6p-1)(6p+1)

Step-by-step explanation:

Now foil. You would get 36p^2+6p-6p-1 so you cancel out your 6ps and that leaves you with (6p-1)(6p+1)

8 0
3 years ago
Hiro has 5 kilograms of potatoes and 2 kilograms of onions
Mekhanik [1.2K]
He has 6 kilograms in all. you add 5 and 2 to get your answer.
5 0
3 years ago
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What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
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What is the discimiant of 9x2+2=10x?
Marina CMI [18]

Answer:

28

Step-by-step explanation:

3 0
3 years ago
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