Y2-y1/x2-x1
(1,14) & (3,4)
y2= 4
y1=14
x2=3
x1=1
So....
(4-14)/(3-1) = -10/2 = -5
The answer should be negative instead of positive, she probably subtracted 4 from 14 instead.
Is there an answer to this equation such as 2x-3+8=4?
D should be the correct answer
Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
