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atroni [7]
2 years ago
15

If x^2-x-6 and x^2+3x-18 hacpve a common factor (x-a) then find the value of a.​

Mathematics
2 answers:
DedPeter [7]2 years ago
3 0

Answer:

a = 3

Step-by-step explanation:

Factor both expressions

x² - x - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (- 1)

The factors are - 3 and + 2 , since

- 3 × 2 = - 6 and - 3 + 2 = - 1 , thus

x² - x - 6 = (x - 3)(x + 2)

-----------------------------------

x² + 3x - 18

consider factors of constant term (- 18) which sum to give the coefficient of the x- term (+ 3)

The factors are + 6 and - 3 , since

6 × - 3 = - 18 and 6 - 3 = + 3 , thus

x² + 3x - 18 = (x + 6)(x - 3)

Both expressions have a common factor of (x - 3)

Compare with (x - a ), then a = 3

Andru [333]2 years ago
3 0
Q. 1) x^2 - x - 6. And 2) x^2 + 3x - 18

Factorise the two expressions
And u get

1) (x-3) (x+2). And 2) (x+6) (x-3)

Common factor is (x-3) so a= -3
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Given that f(x)=x2-1 and g(x)=2x+8 find (g-f)(10)
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Step-by-step explanation:

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