No, Abe is incorrect.
If you don’t know which side is the hypotenuse, you have to try every possibility.
3^ + 4^ = 5^
25 = 25
The triangle is a right triangle. The side which is 5 cm long is the hypotenuse.
Answer:
The sum of the first 37 terms of the arithmetic sequence is 2997.
Step-by-step explanation:
Arithmetic sequence concepts:
The general rule of an arithmetic sequence is the following:
![a_{n+1} = a_{n} + d](https://tex.z-dn.net/?f=a_%7Bn%2B1%7D%20%3D%20a_%7Bn%7D%20%2B%20d)
In which d is the common diference between each term.
We can expand the general equation to find the nth term from the first, by the following equation:
![a_{n} = a_{1} + (n-1)*d](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20a_%7B1%7D%20%2B%20%28n-1%29%2Ad)
The sum of the first n terms of an arithmetic sequence is given by:
![S_{n} = \frac{n(a_{1} + a_{n})}{2}](https://tex.z-dn.net/?f=S_%7Bn%7D%20%3D%20%5Cfrac%7Bn%28a_%7B1%7D%20%2B%20a_%7Bn%7D%29%7D%7B2%7D)
In this question:
![a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6](https://tex.z-dn.net/?f=a_%7B1%7D%20%3D%20-27%2C%20d%20%3D%20-21%20-%20%28-27%29%20%3D%20-15%20-%20%28-21%29%20%3D%20...%20%3D%206)
We want the sum of the first 37 terms, so we have to find ![a_{37}](https://tex.z-dn.net/?f=a_%7B37%7D)
![a_{n} = a_{1} + (n-1)*d](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20a_%7B1%7D%20%2B%20%28n-1%29%2Ad)
![a_{37} = a_{1} + (36)*d](https://tex.z-dn.net/?f=a_%7B37%7D%20%3D%20a_%7B1%7D%20%2B%20%2836%29%2Ad)
![a_{37} = -27 + 36*6](https://tex.z-dn.net/?f=a_%7B37%7D%20%3D%20-27%20%2B%2036%2A6)
![a_{37} = 189](https://tex.z-dn.net/?f=a_%7B37%7D%20%3D%20189)
Then
![S_{37} = \frac{37(-27 + 189)}{2} = 2997](https://tex.z-dn.net/?f=S_%7B37%7D%20%3D%20%5Cfrac%7B37%28-27%20%2B%20189%29%7D%7B2%7D%20%3D%202997)
The sum of the first 37 terms of the arithmetic sequence is 2997.
Answer:
0,-2,-8,-36
Step-by-step explanation:
Answer:
1/12
Step-by-step explanation:
Since the probability of getting heads is 1/2 and the probability of the number cube getting three is 1/6, we multiply.
For every coin flip, there is a 1/6 chance of getting a three. But since there is another condition, we have to multiply. Multiplying both fractions make 1/12.
Using the equations for tangent and secant lines:
Let the unknown length of the line inside the circle = y
6^2 = 3 x (y+3)
Simplify:
36 = 3y+9
Subtract 9 from both sides:
27 =3y
Divide both sides by 3:
Y = 9
Now add to get x:
X = 9 + 3 = 12
X = 12